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 发表于 2024-12-22 09:46:59
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| 这种三角函数后处理也方便 T01 M06
 G54 G90
 S1800 M03
 #1 = #7921 - 500 (P47.x - center500)
 #2 = 500 - #7941 (center500 - P48.X.Z)
 IF [#7944 LT 0] THEN #2 = - #2 (B-90)
 #3 = SQRT[#1 * #1 + #2 * #2](R)
 #4 = ATAN [#1]/[#2] (THETA)
 #5= -67.5(B)
 #6 = [SIN[#4 - #5] - SIN[#4]] * #3 (DELTA X)
 #7 = [COS[#4 - #5] - COS[#4]] * #3 (DELTA Z)
 G00 Z[400. + #7]
 G00 B-67.5
 G90 X[27.955 + #6] Y185.918
 Z[29.441 + #7]
 Z[14.522 + #7]
 G01 X[27.93 + #6] Y-21.918 F2700.
 G00
 X[28.829 + #6] Y-21.922
 Z[14.072 + #7]
 G01 X[28.832 + #6] Y185.922
 G00
 X[29.732 + #6] Y185.926
 Z[13.623 + #7]
 G01 X[29.71 + #6] Y-21.925
 G00
 X[30.609 + #6] Y-21.93
 Z[13.174 + #7]
 G01 X[30.623 + #6] Y185.929
 G00
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